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Python zip(*list)[num]为什么会把列表的一列提取出来

zip()是Python的一个内建函数,它接受一系列可迭代的对象作为参数,将对象中对应的元素打包成一个个tuple(元组),第0个元组对应于所有参数的第0个元素,第1个元组对应于所有参数的第1个元素,依此类推,然后返回由这些tuples组成的list(列表...

mylist=[1,2,3,4,5] for num in mylist: print(num) 用for 变量 in 列表 这种形式

list=['1','2','3','4','5',...'36']Sum_list=0for i in range(0,n): Sum_list+=int(list[i])print(Sum_list)

>>> arr[[10, 11, 12, 13, 14, 15, 16, 17, 18, 19], [11, 12, 13, 14, 15, 16, 17, 18, 19, 20], [12, 13, 14, 15, 16, 17, 18, 19, 20, 21], [13, 14, 15, 16, 17, 18, 19, 20, 21, 22], [14, 15, 16, 17, 18, 19, 20, 21, 22, 23], [15, 16, ...

#!/usr/bin/pythonf = open('myfile.txt','r')lines = f.readlines()names = locals()for line in lines: index = int(lines.index(line))+1 names['list%d' % index] = line.split()print "list1 = " + str(list1)print "list2 = " + str(list2...

import xlwtf = xlwt.Workbook() #创建工作簿sheet1 = f.add_sheet(u'sheet1',cell_overwrite_ok=True) #创建sheetl_=[1,2,3,4,5]for i in range(len(l_)): sheet1.write(0,i,i)#表格的第一行开始写。第一列,第二列。。。。 #sheet1.write(0,0,...

commonest = [1,2,2,2,1,3,4,5,1,1]print(commonest.count(1))需要把数据存储到列表中,列表的count的方法可以统计某个元素出现的次数

import xlrddata = xlrd.open_workbook('excelFile.xls')table = data.sheet_by_index(0) #通过索引顺序获取,0表示第一张表data = [table.cell(i,ord('G')-ord('A')).value for i in range(1, 90)]

# coding: UTF-8blist = []split_char = ' 'with open('b.txt', 'r') as bf: blist = [b.strip().split(split_char) for b in bf]word = '我'print repr(word)for bl in blist: print bl if word in bl: print 'blist[%d][%d]' % (blist.index(b...

import re pattern = re.compile(r'正则') items = re.findall(pattern,你需要匹配的东西) type(items) list 还有其他的 你可以看一下re模块的相关介绍

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